Fair enough. Here are some final words, with an untiltime for the rule.
group
theory
galois
inverse
word
iterate
eliminate
count
Those words may spark some other rule findings. If not, here is the rule.
Step one: Eliminate any consecutive pair of either consonants or vowels. For the purposes of this rule, y counts as a vowel.
Step two: Repeat step one until there are no more pairs.
Step three: The score is the number of remaining vowel-consonant or consonant-vowel pairs (starting with the first consonant). Unpaired letters do not count towards the score.
Why the group theory you may ask? Well...mathy stuff ahead. You have been warned. You know how 5 and -5 sum to zero? This is the additive inverse property. Group theory says change addition to "
general operation"
. And there are some groups (essentially a collection with an operation) where things are their own inverse--when they operate on themselves, they make the identity (like zero--when you operate with the identity, you do nothing to what you operate upon.)
So you can change every consonant to "
c"
and every vowel to "
o"
, and make a word like ccooocococococccoc. Since cc does nothing, and oo does nothing, you can eliminate the pairs to:
ccooocococococccoc
ooocococococccoc
ocococococccoc
ococococococ.
Since there are no pairs left, this gives a score of 6, for 6 "
oc"
pairs.
And Kwerulous--just zex is fine. You solved the rule (I'm pretty sure), after all.
____________________________
Click here to view the secret text
×
First Delver! (I was the first non-tester/dev
to conquer TCB.)
d
/dy