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Caravel Forum : Other Boards : Anything : e^(i*pi) +1 = 0 (Found in a book... and I don't know what it means/how it works)
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zex20913
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icon Re: e^(i*pi) +1 = 0 (+1)  
Stop. You're making math hurt.

0^1 is 0.

In calculus, 0^0 is moreso indeterminate than undefined. Sometimes it is 0, sometimes 1, sometimes it could be 6.2312623. It can be determined under certain circumstances.

But 0^1 is always 0.

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02-11-2008 at 11:26 PM
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Beef Row
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icon Re: e^(i*pi) +1 = 0 (0)  
BeefontheBone wrote:
Beef Row wrote:
TripleM wrote:
And Dex, you mean only non trivial function ;)

Well, I don't see how c*e^x is more trivial than e^x. And since c*e^x actually includes the trivial 0 case, better to just say that IT is the only function which is its own derivative.
Other than x=0, which is probably the more trivial example TripleM was referring to :)

Ummm... I think you mean f(x) = 0. And what happens to c*e^x when you set c = 0? As I noted in the post this "actually includes the trivial 0 case".

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02-12-2008 at 12:29 AM
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captainzakku
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icon Re: e^(i*pi) +1 = 0 (0)  
zex20913 wrote:
Stop. You're making math hurt.

0^1 is 0.

In calculus, 0^0 is moreso indeterminate than undefined. Sometimes it is 0, sometimes 1, sometimes it could be 6.2312623. It can be determined under certain circumstances.

But 0^1 is always 0.

Now lets make a contest to see who can come up with the most original new way to represent 6.2312623, such that people might actually tatoo that number on themselves...

Oops, sorry, I thought if contest threads could randomly disolve into mathematical arguments, maybe it would work the other way around too.

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02-12-2008 at 02:54 AM
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calamarain
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icon Re: e^(i*pi) +1 = 0 (0)  
Then how about an engineering puzzle?

What is the air speed velocity of an unladen swallow?

(An african swallow, before you ask)

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02-12-2008 at 03:14 AM
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TripleM
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icon Re: e^(i*pi) +1 = 0 (0)  
Beef Row wrote:
Ummm... I think you mean f(x) = 0. And what happens to c*e^x when you set c = 0? As I noted in the post this "actually includes the trivial 0 case".

Yeah, its just not how you normally state things like this mathematically.

Let just use wikipedia to settle it once and for all.. (not that I'm saying you're incorrect, just arguing over the fine details :P)

the exponential function f(x) = e^x is important in part because it is the unique nontrivial function (up to multiplication by a constant) which is its own derivative

Multiplication by a constant includes 0, but its just more standard to still say 'nontrivial'.

[Last edited by TripleM at 02-12-2008 06:20 AM]
02-12-2008 at 06:20 AM
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Walkaway Joe
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icon Re: e^(i*pi) +1 = 0 (0)  
OK, I'm no mathemetician. I Just need some help solving a possible, that uses this equation to do so. Here's the puzzle:




e to the i pi plus 1 equals zero

Published COordinatess: N 60° 28.159 W 151° 08.828

The correct coordinates are N 60° 28.xxx W 151° 08.xxx. The title is the puzzle that yields the decimals for the minutes.

An additional hint given is: The published coordinates are cut from four to six. The true coordinates are cut from one to three.

So, can anyone tell me what the numbers are that should be used to replace the xxx in each part of the coordinates?
08-20-2011 at 03:11 PM
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Rabscuttle
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icon Re: e^(i*pi) +1 = 0 (0)  
... that is an odd first post.

You trying to solve one of those puzzle competitions?

Anyway, you should look up the decimal expansions of e and pi.
08-20-2011 at 03:28 PM
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Walkaway Joe
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icon Re: e^(i*pi) +1 = 0 (0)  
I don't know that I'd call it a competition per se. But yes, something similar. WHere would I find those expansions you mention?

08-20-2011 at 03:35 PM
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Walkaway Joe
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icon Re: e^(i*pi) +1 = 0 (0)  
Rabscuttle wrote:
... that is an odd first post.

You trying to solve one of those puzzle competitions?

Anyway, you should look up the decimal expansions of e and pi.
Actually, I got it. 314 and 271. HAve a good day!!
08-20-2011 at 03:39 PM
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west.logan
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icon Re: e^(i*pi) +1 = 0 (0)  
I don't get it. The first three digits of pi and e, truncated? What kind of a puzzle is that?

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08-20-2011 at 03:43 PM
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Rabscuttle
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icon Re: e^(i*pi) +1 = 0 (0)  
I'm curious if there was anything else involved in the puzzle - I don't see how you're meant to get the solution without the additional hint.
08-20-2011 at 03:43 PM
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Walkaway Joe
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icon Re: e^(i*pi) +1 = 0 (0)  
Rabscuttle wrote:
I'm curious if there was anything else involved in the puzzle - I don't see how you're meant to get the solution without the additional hint.

I was going to post the link to the puzzle in it's entirety, but apparently I don't have enough "Rank points" to do so.

If you go to the website geocaching.com, and search for the cache GC32DNT, you will find the puzzle there.

[Last edited by Walkaway Joe at 08-20-2011 04:46 PM]
08-20-2011 at 04:44 PM
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Tahnan
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icon Re: e^(i*pi) +1 = 0 (0)  
Oh, geocaching. You have managed to find entirely the wrong forum to ask about the equation. :-)

(Well, not entirely, because we're generally smart people who understand why e-to-the-i-pi equals negative one, but anyway.)
08-21-2011 at 02:01 AM
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Syntax
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icon Re: e^(i*pi) +1 = 0 (0)  
3.5 year necro for an obscure geo-caching puzzle with not enough hints.

I vote this as the post of the year :) (this year)
08-28-2011 at 10:17 AM
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coppro
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icon Re: e^(i*pi) +1 = 0 (0)  
The clue is in the "published coordinates" which have the next three digits in the respective decimal expansions.
08-30-2011 at 02:25 AM
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Rabscuttle
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icon Re: e^(i*pi) +1 = 0 (0)  
Yeah, I saw that, but I can't see any implicit reason why you should replace them with the first three digits, rather than say, the next three digits.
08-30-2011 at 02:32 AM
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DiMono
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icon Re: e^(i*pi) +1 = 0 (0)  
Rabscuttle wrote:
Yeah, I saw that, but I can't see any implicit reason why you should replace them with the first three digits, rather than say, the next three digits.
There's a description that goes with the puzzle, and you're meant to solve it with the help of a GPS.

"The cache is about 130 ft from a horse and four wheeler trail, buried in the ground, camoed but easy to recognize."

So if you tried the next 3 digits, you'd be in the wrong place. I suppose it would come down to quick trial-and-error.

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08-31-2011 at 05:34 PM
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