agaricus5 wrote:
I suppose it is to have each prisoner say the colour of the hat of the person in front. That way, 19 of the prisoners will be saved, and only the first one will die.
That won't work, because though the second person will know what colour his hat is, he has to say the colour of the one in front. So if they are different, one of the two will die.
My solution should work though (I think).
[Edited by The_Red_Hawk on 01-01-2004 at 01:40 AM GMT]
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