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Rabscuttle
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30 + 35 + 2 = 67 :)

---

This is a little bit mathsy, but not too much.

Pursued by a serpent, Beethro was running along a corridor when he came to a long row of orbs stretching some way. With the serpent close behind there was no time to make a thorough count, but there were definitely less than a hundred.

Beyond the orbs was a row of closed doors - one opposite each orb. "That seems simple enough," he muttered, and swinging his sword out to the side, he whacked each orb as he passed it. But it soon clear that the orbs weren't wired so simply. As Beethro hit the first orb, every single door swung open. As he hit the second orb, every second door swung shut. The third orb toggled every third door, the fourth orb toggled every fourth door and so on down the line until the final orb toggled the last door.

Leaping through a gap and escaping the snake, Beethro made his way back to the doors. To his dismay he found that he'd only managed to open 7 of them - the rest were shut tight.

"Maybe I should have only hit the odd orbs?" he pondered. After a moments thought, he said "No, that only would have opened four extra doors."

How many doors were there?
10-21-2004 at 08:13 AM
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wackhead_uk
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This might just be me, but I think I've seen this one on here before, no offence meant.
10-21-2004 at 09:27 AM
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Rabscuttle
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I've seen it elsewhere, because that's where I sto.. "researched" it from. I don't think it's been on the DROD forums before now - a simple search didn't find it, anyway.
10-21-2004 at 10:02 AM
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Mattcrampy
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We did have one that was very similar, but this one is different enough to be interesting. The first one wanted us to find how many open doors there were following the pattern. This one gives us a new pattern as well and asks us to find both open and closed.

Matt

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10-21-2004 at 12:46 PM
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Rabscuttle
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Oh yeah, there it is. I was searching for a differently worded puzzle. (Actually, first I was searching for the solution, but that turned up 42 pages or stuff (not surprising, given the word I chose :D))
10-21-2004 at 01:02 PM
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DiMono
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Solution

Alright... the basis of this puzzle is that only the first door, and doors whose number are even powers of prime numbers, or two even powers of primes multiplied together, will be opened. All other doors will be hit an even number of times, and remain closed. The doors that can open are:

1^1 = 1 (1)
2^2 = 4 (1 2 4)
3^2 = 9 (1 3 9)
2^4 = 16 (1 2 4 8 16)
5^2 = 25 (1 5 25)
4*9 = 36 (1 2 3 4 6 9 12 18 36)
7^2 = 49 (1 7 49)
2^6 = 64 (1 2 4 8 16 32 64)
3^4 = 81 (1 3 9 27 81)

There's also another, being:


Since only seven of these eight doors opened, there were less than 64 doors and more than 48. So far, so good.

If only odd orbs are hit, all the original seven are still open, and newly opened doors would be the ones with an odd number of even divisors. Doors with an even number of divisors will remain unchanged, such as 4 (1, 2, 4), 16 (1, 2, 4, 8, 16), and 64 (1, 2, 4, 8, 16, 32, 64).

The other doors will be obtained by multiplying the odd powers of 2 (2, 8, 32) by the odd numbered doors that opened above. This is the only way to obtain a number with an odd number of even divisors. These numbers will be:

2^1 * 1^1 = 2 (1 2)
2^3 * 1^1 = 8 (1 2 4 8)
2^1 * 3^2 = 18 (1 2 3 6 9 18)
2^5 * 1^1 = 32 (1 2 4 8 16 32)
2^1 * 5^2 = 50 (1 2 5 10 25 50)
2^3 * 3^2 = 72 (1 2 3 4 6 8 9 12 18 24 36 72)

Since only 4 of these doors are opened, there must be less than 50 doors. Therefore, there are 49.


My turn:

This may look like a math puzzle, but it is in fact a pure logic puzzle. Substitute single digits for the letters A, B, C, D and E in the following equation such that you arrive at a valid solution:
A B C D E
        4
---------
E D C B A
Just to state the obvious, both As must hold the same value, as must both Bs, etc. As well, simply assigning all digits to be 0 is a cop-out.


Edit: I realised I'd made an error in my solution to Rabscuttle's puzzle, and it's now been corrected. The answer is 49.

[Edited by DiMono at Local Time:11-07-2004 at 06:42 AM]

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11-07-2004 at 06:04 AM
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Schik
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DiMono wrote:
A B C D E
        4
---------
E D C B A
I assign all of them the value zero.


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11-07-2004 at 06:17 AM
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DiMono
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Schik wrote:
DiMono wrote:
A B C D E
        4
---------
E D C B A
I assign all of them the value zero.
I call shenanigans, and revise my puzzle :P

Edit: Actually, since zero is only written with one digit, I don't have to revise my puzzle at all because the answer is invalid. I've done it anyway though, for clarity.

[Edited by DiMono at Local Time:11-07-2004 at 06:31 AM]

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11-07-2004 at 06:26 AM
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Rabscuttle
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From column 5, A must be even.
From column 1, A must be 2 or less.
Therefore A = 2

From column 5, E is 8 or 3
From column 1, E is 8 or 9
Therefore E = 8

From column 4, B is odd (due to carrying 3)
From column 2, B is 2 or less (due to not carrying anything)
Therefore B = 1

From column 4, D is 7 or 2
From column 2, D is 4, 5, 6 or 7
Therefore D = 7

From column 3, C * 4 + 3 = 30 + C
Therefore C = 9

Complete solution:
21978 * 4 = 87912


---

hrm.. this one is easy (if you've heard it before)

A car pulled up in front of a hotel. At once the owner of the car knew that he was bankrupt. Why?

[Edited by Rabscuttle at Local Time:11-07-2004 at 08:14 AM: misnumber]
11-07-2004 at 08:12 AM
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Mattcrampy
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By the rules of the game, I'm sitting out because I know this one.

Matt

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11-07-2004 at 12:02 PM
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Fafnir
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Was he the hotel owner and had the hotel burned down/been blown up/suffered a miniature earthquake etc.?

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11-07-2004 at 01:45 PM
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Rabscuttle
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No, he was not the owner of the hotel.

Nor had the hotel suffered a miniature earthquake or anything else.
11-08-2004 at 12:36 AM
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rowrow
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He was playing Monopoly.
Heres a good puzzle:Make a 4x4 of numbers 1 through 16 including 16 and 1 that all of the rows add up to 34.such as 15 15 3 1. It adds to 34 but it uses 15 2x. You can only use each number once and you must use all.

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11-08-2004 at 03:05 AM
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DiMono
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rowrow wrote:
He was playing Monopoly.
Heres a good puzzle:Make a 4x4 of numbers 1 through 16 including 16 and 1 that all of the rows add up to 34.such as 15 15 3 1. It adds to 34 but it uses 15 2x. You can only use each number once and you must use all.
I think this falls under the realm of pure math puzzles that we're trying to avoid.

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11-08-2004 at 04:20 AM
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rowrow
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It only takes addition. I think he only said you can't do complicated math problems.

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11-08-2004 at 04:27 AM
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AlefBet
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Is this what you're looking for?
Click here to view the secret text
Or, if you want to include the diagonals:
Click here to view the secret text



[Edited by AlefBet at Local Time:11-08-2004 at 06:24 AM]

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++Adam H. Peterson
11-08-2004 at 06:19 AM
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rowrow
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Oooh you got it. I was thinking of
Click here to view the secret text

Next.
Edit:It posted it 2x. I think it was b/c I saw a mistake and I stopped it so I guess it posted it nevertheless.

[Edited by rowrow at Local Time:11-08-2004 at 06:32 AM]

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11-08-2004 at 06:29 AM
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AlefBet
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Okay, this is a puzzle of my own making, so I have no idea how hard it is. If people get stumped, I may have to post some clues.

Under what constraint was this snippet composed:
Uh the no status diet pages can. There, I'll finally make jaws quiver tantalizingly; exhibit.

[Edited by AlefBet at Local Time:11-08-2004 at 06:14 PM: fixed a flaw in the snippet]

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11-08-2004 at 06:34 AM
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Rabscuttle
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[Edited by Rabscuttle at Local Time:11-08-2004 at 07:43 AM]
11-08-2004 at 07:42 AM
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http://beepsandbloops.wordpress.com/
11-08-2004 at 08:16 AM
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AlefBet
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RoboBob3000 wrote:
Is it a pangram of your own creation, or is there more to it then just that?
It is supposed to be. But there's more to it than that. The omission of an F is an error, but it's coupled with the inclusion of a Y. They should have been included or excluded together.

Someone else creating something under the same constraint might have come up with:
Ty rut tire wore quip though Jeff kidded slyly after; zoo? Axes. Cars, voom beyond.
The reason I didn't is because of one of my personal preferences which is somewhat unique.

Here's a version that corrects the error:
Uh the no status diet pages can. There, I'll finally make jaws quiver tantalizingly; exhibit.
I'll go correct it on the original post.

[Edited by AlefBet at Local Time:11-08-2004 at 06:13 PM]

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11-08-2004 at 06:09 PM
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AlefBet
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There's been some inactivity, so here are a few more examples of snippets constructed according to the rule:
Huh the neon Santa did gaped cost. Rush, that'll fry Kim's jigsaw quicksilver zone; boxed.
Uh teeth on ash died gasps once. Or, she'll safely skim jeweled vanquishing zoos; flexibly.
Huh heth note Shannon said sponges act. Nor, else's fantasy marked jewelry quavered zeal; bruxism.
Also, the example I gave above (starting with "Ty rut tire...") is not constructed according to the same rule as these, but it is constructed according to a similar rule.

[Edited by AlefBet at Local Time:11-09-2004 at 10:05 AM]

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11-09-2004 at 10:02 AM
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Nillo
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AlefBet wrote:
Huh the neon Santa did gaped cost. Rush, that'll fry Kim's jigsaw quicksilver zone; boxed.
Uh teeth on ash died gasps once. Or, she'll safely skim jeweled vanquishing zoos; flexibly.
Huh heth note Shannon said sponges act. Nor, else's fantasy marked jewelry quavered zeal; bruxism.
All the first words contain the letter U, the next E, the next O, and so on.
Is that it?

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11-09-2004 at 01:46 PM
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AlefBet
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Nillo wrote:
AlefBet wrote:
Huh the neon Santa did gaped cost. Rush, that'll fry Kim's jigsaw quicksilver zone; boxed.
Uh teeth on ash died gasps once. Or, she'll safely skim jeweled vanquishing zoos; flexibly.
Huh heth note Shannon said sponges act. Nor, else's fantasy marked jewelry quavered zeal; bruxism.
All the first words contain the letter U, the next E, the next O, and so on.
Is that it?
You're on the right track, but that's not all. If it were, there's no way I should have expected you to get it from only one example originally.

[Edited by AlefBet at Local Time:11-09-2004 at 07:22 PM]

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11-09-2004 at 07:19 PM
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mrimer
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The punctuation seems awfully suspicious...I wonder how it's involved.

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Gandalf the Grey. That was my name.
I am Gandalf the White.
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11-09-2004 at 07:41 PM
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TripleM
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I haven't fully worked out the rule, but I think this is something relatively important:
Click here to view the secret text

11-09-2004 at 11:56 PM
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AlefBet
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Another day, and it's time for another hint.

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11-10-2004 at 06:04 PM
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mrimer
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Ah-hah! The words follow a progressive pattern sequence. Each one must use the two letters from the same finger position on each side on the keyboard. One row of keys is used, then the second, then the third, each with the same finger sequence.

The matching letters are:
uh et on as id pg .c ,r 'l yf km jw qv ;z bx (Dvorak)
ty ru ei wo qp gh fj dk sl a; bn vm c, x. z? (Qwerty)

Each word can only use the two new letters, and the ones that have been used previously.

[Edited by mrimer at Local Time:11-10-2004 at 06:52 PM]

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Gandalf? Yes... That's what they used to call me.
Gandalf the Grey. That was my name.
I am Gandalf the White.
And I come back to you now at the turn of the tide.
11-10-2004 at 06:48 PM
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Fafnir
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You just had to post right then, didn't you? :P I thought I'd worked it out - it used every key from each row of the keyboard in sequence. I didn't get the symmetry though, so the trophy is yours.

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11-10-2004 at 06:55 PM
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AlefBet
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Mike gets it.

I designed the phrase to be a sort of "crash-course" typing tutor introduction to the Dvorak keyboard layout. Each word introduces exactly two new letters (or punctuation) and the snippet progresses along the home row, then the others, in a manner you might expect for a typing tutor.

(The QWERTY version doesn't work like that, though, because it's pretty much impossible to form any good words using only letters on the home row. So I had to improvise a new sequence for that example.)

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11-10-2004 at 06:56 PM
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