Blondbeard
Level: Smitemaster

Rank Points: 1486
Registered: 03-31-2005
IP: Logged

Yes. That is the obvious That isn't the answer I was looking for. I'll add some hints later on.

---

[Last edited by Blondbeard at 10-28-2006 09:29 AM]

TripleM
Level: Smitemaster
Rank Points: 1373
Registered: 02-05-2003
IP: Logged

Hmm.. I was about to (in fact, I did, then I deleted it) guess that it was a proof of Pythagoras' Theorem, but that is actually a slightly different picture.

krammer
Level: Smitemaster

Rank Points: 904
Registered: 02-12-2003
IP: Logged

File: puzzleblondbeard.PNG (2.4 KB)
Downloaded 58 times.
License: Public Domain

To save those on slow connections, I managed to reduce the size of your file to less than 0.5% of the one you posted. Please don't use bmp unless absolutely necessary...

____________________________
+++ Divide by Cucumber Error +++ Please Reinstall Universe and Reboot +++

"Oook!"

Maurog
Level: Smitemaster

Rank Points: 1501
Registered: 09-16-2004
IP: Logged

File: puzzleblondbeard.PNG (2.9 KB)
Downloaded 646 times.
License: Public Domain

Hmm, is it maybe the fact that if you "unflip" the triangles, you get a square again?


____________________________
Slay the living! Raise the dead!
Paint the sky in crimson red!

Blondbeard
Level: Smitemaster

Rank Points: 1486
Registered: 03-31-2005
IP: Logged

Well... I don't know how to treat this. The correct answer has been posted, but in a slightly odd form. In fact it is a proof of Pythagoras Theorem. There are multiple pictures wich proves the theorem, but I like this one. Name the triangles sides a, b and c (which is also the side of the large square). It should be easy to see that a squared plus b squared is indeed equal to c squared. Since you actually did post this, Tripple M, I say you gave the correct answer.

zex20913
Level: Smitemaster

Rank Points: 1723
Registered: 02-04-2003
IP: Logged

There are literally an infinite number of proofs for the Pythagorean Theorem. At least, according to one book that listed thousands of them.

I see this proof now (had to think about it for a bit before I discovered (a-b)^2), but the proof I learned first (and best) comes from Maurog's picture, where we have (a+b)^2. I just see that more clearly.

____________________________

Ezlo
Level: Smitemaster

Rank Points: 1214
Registered: 01-08-2006
IP: Logged

If that was in 3D, it would make quite a nice vase.

TripleM
Level: Smitemaster
Rank Points: 1373
Registered: 02-05-2003
IP: Logged

Yeah, I guess it does work with this picture as well, though the proof using the other picture (which is almost identical to yours except the triangles are flipped the other way, so its easy to mix them up by accident, which is why I still posted that guess ) seems to be a lot more clear. Oh well, now I'll have to think up a puzzle..

TripleM
Level: Smitemaster
Rank Points: 1373
Registered: 02-05-2003
IP: Logged

OK, I haven't come up with anything yet, but I'll continue to think; I've heard so many good ones but none come to mind right now. If anyone else knows one, feel free to take over.

jamesdenem
Level: Master Delver
Rank Points: 203
Registered: 07-03-2006
IP: Logged

Well, I guess since nobody else has any ideas, I might as well post one.

What is the next number(Shown as '?') of the following sequence, and why?

4, 3, 3, 5, 4, 4, ?

____________________________
This signature intenionally left blank. Disregard any text you may find here, because it is probably just your imagination, and not a signature in any way. We mean it, don't believe that there is text here.

jbluestein
Level: Smitemaster

Rank Points: 1670
Registered: 12-23-2005
IP: Logged

jamesdenem wrote:
Well, I guess since nobody else has any ideas, I might as well post one.

What is the next number(Shown as '?') of the following sequence, and why?

4, 3, 3, 5, 4, 4, ?

3.

____________________________
"Rings and knots of joy and grief, all interlaced and locking." --William Buck

---

[Last edited by jbluestein at 11-02-2006 07:19 PM]

Kevin_P86
Level: Smitemaster

Rank Points: 535
Registered: 06-28-2005
IP: Logged

Yes, duh. I was thinking:

Instead of


____________________________
+++++[>+++++<-]>[>+++>++++>+++++<<<-]>.>+.>-------.<++++.+++++.

jamesdenem
Level: Master Delver
Rank Points: 203
Registered: 07-03-2006
IP: Logged

Pretty quick response, jbluestein got the number, and Kevin_P86 got the reason. You two can decide amond yourselves who wants to post the next puzzle, and if neither of you do, I have a much more difficult one in mind...

____________________________
This signature intenionally left blank. Disregard any text you may find here, because it is probably just your imagination, and not a signature in any way. We mean it, don't believe that there is text here.

Kevin_P86
Level: Smitemaster

Rank Points: 535
Registered: 06-28-2005
IP: Logged

jbluestein got it first, so I think it should be his turn. But I can come up with something if he prefers...

____________________________
+++++[>+++++<-]>[>+++>++++>+++++<<<-]>.>+.>-------.<++++.+++++.

jbluestein
Level: Smitemaster

Rank Points: 1670
Registered: 12-23-2005
IP: Logged

Kevin_P86 wrote:
jbluestein got it first, so I think it should be his turn. But I can come up with something if he prefers...

Go for it. Sick baby means little sleep. Means brain no work too good.


____________________________
"Rings and knots of joy and grief, all interlaced and locking." --William Buck

Kevin_P86
Level: Smitemaster

Rank Points: 535
Registered: 06-28-2005
IP: Logged

File: puzzle.jpg (33.9 KB)
Downloaded 459 times.
License: Public Domain

Ok. This is likely one that everyone has seen before at some point, but it's still a good one. Your task is to draw a continuous curving line (in two dimensions) that passes through each line segment of this diagram exactly once (i.e. it must start and end at the same point). Is it possible? What if the line need not start and end at the same point? Is it possible then?



To avoid confusion, I have labeled the 16 line segments that need to be crossed. The order in which the segments are crossed is unimportant.

____________________________
+++++[>+++++<-]>[>+++>++++>+++++<<<-]>.>+.>-------.<++++.+++++.

---

[Last edited by Kevin_P86 at 11-02-2006 10:38 PM]

coppro
Level: Smitemaster
Rank Points: 1308
Registered: 11-24-2005
IP: Logged

Using geometry, I don't even need to try to tell you that it isn't possible, because the two bottom sections each have 5 surrounding segments, and there are 9 on the outside. Since 5 and 9 are odd numbers, 3 odd numbers makes it unsolvable, whether or not it is continuous.

Kevin_P86
Level: Smitemaster

Rank Points: 535
Registered: 06-28-2005
IP: Logged

And the middle box on the top has an odd number (5) as well

Your turn, coppro.

____________________________
+++++[>+++++<-]>[>+++>++++>+++++<<<-]>.>+.>-------.<++++.+++++.

agaricus5
Level: Smitemaster
Rank Points: 1838
Registered: 02-04-2003
IP: Logged

coppro wrote:
Using geometry, I don't even need to try to tell you that it isn't possible, because the two bottom sections each have 5 surrounding segments, and there are 9 on the outside. Since 5 and 9 are odd numbers, 3 odd numbers makes it unsolvable, whether or not it is continuous.

I think you can also convert the diagram to a graph, with the spaces inside the rectangle as nodes, and edges as arcs, and use this to solve the puzzle. There are 9 arcs to the outside, and three nodes with 5 arcs inside the rectangle. So, the puzzle is unsolvable, because you will end up with at least two "unpaired" arcs, where a "pair" of arcs is a pair that allows you to enter and then leave a particular node. The unpaired arcs allow you to enter a node, but there won't be any arcs left leaving from that node (it's an odd, single arc), so you can't leave.

____________________________
Resident Medic/Mycologist

Kevin_P86
Level: Smitemaster

Rank Points: 535
Registered: 06-28-2005
IP: Logged

agaricus5 wrote:

coppro wrote:
Using geometry, I don't even need to try to tell you that it isn't possible, because the two bottom sections each have 5 surrounding segments, and there are 9 on the outside. Since 5 and 9 are odd numbers, 3 odd numbers makes it unsolvable, whether or not it is continuous.

I think you can also convert the diagram to a graph, with the spaces inside the rectangle as nodes, and edges as arcs, and use this to solve the puzzle. There are 9 arcs to the outside, and three nodes with 5 arcs inside the rectangle. So, the puzzle is unsolvable, because you will end up with at least two "unpaired" arcs, where a "pair" of arcs is a pair that allows you to enter and then leave a particular node. The unpaired arcs allow you to enter a node, but there won't be any arcs left leaving from that node (it's an odd, single arc), so you can't leave.

Yes, exactly. After converting it to a graph the object is to find an Euler Circuit in the first case, and an Euler Path in the second case. We have theorems which state an Euler Circuit exists iff all vertices have even degree (and the graph is connected, of course), and we have an Euler Path iff 0 or 2 vertices have an odd degree (and the graph is connected).

____________________________
+++++[>+++++<-]>[>+++>++++>+++++<<<-]>.>+.>-------.<++++.+++++.

Syntax
Level: Smitemaster
Rank Points: 1218
Registered: 05-12-2005
IP: Logged

Kevin_P86 wrote:
Yes, duh. I was thinking:

Click here to view the secret text

×"One", "Two", "Three", ...

Instead of

Click here to view the secret text

×"Zero", "One", "Two", "Three", ...

There are -1 types of people in the world... those who initialise arrays with 1 vs those who initialise them with 0

Kevin_P86
Level: Smitemaster

Rank Points: 535
Registered: 06-28-2005
IP: Logged

Syntax wrote:

Kevin_P86 wrote:
Yes, duh. I was thinking:

Click here to view the secret text

×"One", "Two", "Three", ...

Instead of

Click here to view the secret text

×"Zero", "One", "Two", "Three", ...

There are -1 types of people in the world... those who initialise arrays with 1 vs those who initialise them with 0

I don't think I've EVER initialized an array with 1's... and I've initialized A LOT of arrays in my day! I assumed it would start with 1 because that's the only way I've seen this puzzle before...

____________________________
+++++[>+++++<-]>[>+++>++++>+++++<<<-]>.>+.>-------.<++++.+++++.

MartianInvader
Level: Master Delver
Rank Points: 126
Registered: 01-30-2004
IP: Logged

File: puzzle.jpg (67.1 KB)
Downloaded 336 times.
License: Public Domain

Kevin_P86 wrote:

To avoid confusion, I have labeled the 16 line segments that need to be crossed. The order in which the segments are crossed is unimportant.

Hehe... you managed to cause confusion with the labeling. Thought I'd post this since it took me a little while to make. It's what happens when you don't read the puzzle closely enough.



____________________________
Yes, I very rarely post. But I DO keep coming back to check the forum.

---

[Last edited by MartianInvader at 11-04-2006 12:36 AM]

Maurog
Level: Smitemaster

Rank Points: 1501
Registered: 09-16-2004
IP: Logged

File: solution.JPG (13.1 KB)
Downloaded 327 times.
License: Public Domain

Actually, there is a solution, and all the people using Euler are wrong. The answer lies in Kevin_86's ingenious use of the word "segment" as opposed to say "edge". These things are segments, they have width and height, and there are two ways to cross any of them - horizontally and vertically. Here is an example of a solution crossing all the segments and ending in the same spot:

____________________________
Slay the living! Raise the dead!
Paint the sky in crimson red!

Mattcrampy
Level: Smitemaster

Rank Points: 2388
Registered: 05-29-2003
IP: Logged

I don't care if this is the intended answer or not, that's damn clever.

____________________________
What do you call an elephant at the North Pole?

agaricus5
Level: Smitemaster
Rank Points: 1838
Registered: 02-04-2003
IP: Logged

Maurog wrote:
Actually, there is a solution, and all the people using Euler are wrong. The answer lies in Kevin_86's ingenious use of the word "segment" as opposed to say "edge". These things are segments, they have width and height, and there are two ways to cross any of them - horizontally and vertically.

That is an ingenious interpretation of the word "segment", I agree, but I don't agree with you about your definition of the word "segment". A segment is a portion or piece of something, but the word "segment" doesn't necessarily define the dimensions of an object. If I told you I am thinking of a "line segment", would you say the "line" I'm thinking of has one or two dimensions?

Therefore, you can't say that either answer is wrong; you can only say that each answer is correct, given a certain assumption about the puzzle.

____________________________
Resident Medic/Mycologist

---

[Last edited by agaricus5 at 11-04-2006 02:40 PM]

Tahnan
Level: Smitemaster

Rank Points: 2459
Registered: 11-14-2005
IP: Logged

(poke poke)

RoboBob3000
Level: Smitemaster

Rank Points: 1980
Registered: 10-23-2003
IP: Logged

The answer is Eppoke, Oklahoma.

____________________________
http://beepsandbloops.wordpress.com/

Mattcrampy
Level: Smitemaster

Rank Points: 2388
Registered: 05-29-2003
IP: Logged

RoboBob3000 wrote:
The answer is Eppoke, Oklahoma.

But what is the question? "What is a surprisingly good holiday destination?" "What town will give birth to the Antichrist?" "What town (including state) is an anagram of 'A Meek Polka Hoop'?"

____________________________
What do you call an elephant at the North Pole?

agaricus5
Level: Smitemaster
Rank Points: 1838
Registered: 02-04-2003
IP: Logged

RoboBob3000 wrote:
The answer is Eppoke, Oklahoma.

Actually, the answer is this.

Edit: Is there something wrong with this joke here? No-one posted a puzzle, so I can't see the harm in replying to Rabscuttle.

Of course, it might be a random negative modder, but the question is then: "why"?

____________________________
Resident Medic/Mycologist

---

[Last edited by agaricus5 at 11-12-2006 04:40 PM]