On further investigation, the behavior here seems to be as follows.
-Aumtlich beams are processed in the move order of the aumtlich.
-When a new beam is processed, first it checks if that beam destroys any orbs. If it did, and another beam was blocked by that orb, that beam will effectively "
fire again"
, destroying any broken orbs in its path and turning cracked orbs into broken orbs.
-However, if the unblocked beam destroys any orbs and unblocks any other beams, those beams' effects (at least on orbs) will NOT be checked.
So I was going to think through how to include a south-facing aumtlich using these rules, but it turns out that's unnecessary. The rules still helped me to come up with a setup that worked without one, though.
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(Note: I know the proper plural of aumtlich is aumtlich, but I feel it will be less confusing to explain this if I pretend it's aumtlichs.)
Place aumtlichs at 1-8, in that relative move order. The last activates the north plate and can then be shoved in the pit (or just left facing any direction other than south). Actually the ordering isn't that strict, as I'll explain below.
I've marked the 9s for a different reason. If an aumtlich stands in one of those spots and faces diagonally towards the middle, it will break one of the two outer orbs. By doing this on both sides, you only need to destroy the 2-by-4 rectangle of orbs during the main event. For this step, you can either try to use the ninth aumtlich on both sides before shoving it onto the north plate, or use your invisibility to lead it to the diagonal arrows afterwards.
So what happens here is, the diagonal aumtlichs damage the northern orbs in each set of four. Then, we have two horizontal aumtlichs facing each of those sets; the upper aumtlich of those two destroys the upper orbs, causing the diagonal beams to "
fire again"
and damage the lower orbs. Finally, the lower aumtlich beam destroys the now-broken orbs.
Any move order that meets those conditions will work, though if you don't want to wrap your head around this nonsense to figure out an alternate one (for optimization purposes?), just follow the 1-8 order in the above image.
