×The adjacent 2 and 5 mean all three squares to the right of the 5 are mines. Two of these touch the 2 above the target, so the target itself is free.

×Fill in the obvious mine in the third column. Just above it are two 3s, the upper one touching one mine already, the lower one touching two. Therefore, there is an additional free square touching the lower one, i.e. the square three above the target. Thus, one and only one of the unknowns below this is a mine, so the target itself is free.

By the way, there's an error in the grid -- the 3 at the top means that the top two unknowns are both mines, which contradicts the 2 below the 3.

×
The T is a mine.

0 1 O 1 0 0 1 J 1 0
1 3 P 3 2 2 3 K 2 0
Q R N M L G F E 2 1
- - T - - H 4 D - -
- - 3 2 3 I 4 C - -
- - 1 0 1 A 3 B - -

Either A or I is a mine, but not both. Using the 3 between A and B, this means that B and C are both mines.
So, that places 3 of the 4 mines around the 4 between I and C. Either H or D is a mine, but not both.
E is a mine: only one of J and K is a mine, so the 2 next to K needs another one.
Only one of F and G is a mine, so L is a mine (the 2 above G)
N is a mine since only one of O and P and only one of Q and R are mines, and the 3 in the top left corner needs one more.
The board now looks like this:

0 1 O 1 0 0 1 J 1 0
1 3 P 3 2 2 3 K 2 0
Q R * M * G F * 2 1
- - T - - H 4 D - -
- - 3 2 3 I 4 * - -
- - 1 0 1 A 3 * - -

So, one of O and P is a mine, so the 3 above M has 3 mines, so M is safe. That means G is a mine, F is safe.

0 1 O 1 0 0 1 J 1 0
1 3 P 3 2 2 3 K 2 0
Q R * . * * . * 2 1
- - T - - H 4 D S U
- - 3 2 3 I 4 * - -
- - 1 0 1 A 3 * - -

D is safe since one of S and U is a mine, and the 2 above S already has one mine to the left.
One of H and I is a mine (the 4 between H and D), so A is a mine (so that the 4 to the left of I has 4). This means that I is safe and H is a mine.

0 1 O 1 0 0 1 J 1 0
1 3 P 3 2 2 3 K 2 0
Q R * . * * . * 2 1
- - T W V * 4 . S U
- - 3 2 3 . 4 * - -
- - 1 0 1 * 3 * - -

Now, only one of V and W is a mine, and the 2 below W needs another mine, so T must be a mine.

0 1 - 1 0 0 1 - 1 0
1 3 - 3 2 2 3 - 2 0
- - * . * * . * 2 1
- - * - - * 4 . - -
- - 3 2 3 . 4 * - -
- - 1 0 1 * 3 * - -

From here, I think you need to guess, though in the original game, unveiling the numbers in the safe squares is guaranteed to lead to more deductions.